Question

17. A trapezium ABCD has sides AB and DC parallel
A straight line parallel to the diagonal AC cuts AB
at E and BC at F. Prove that triangles AED and
ACF are equal in area.

​

Answer 1

Answer:

This pic is the correct answer

Mark it as brainliest

Answer 2

Area of  ΔADE = Area of  ΔACF  in a Trapezium ABCD AB | DC & EF ║ AC  such that EF Cuts AB at E & BC at F

Step-by-step explanation:

A trapezium ABCD has sides AB and DC parallel

A straight line parallel to the diagonal AC cuts AB

at E and BC at F

Lets join CE

Now ΔACE  & ΔACF

EF ║ AC  & Same Base AC

Two triangles having same Base & Between Parallel lines have Equal Area

=> Area of ΔACE  = Area of  ΔACF

Now ΔACE  & ΔADE

has same Base AE  

& AE ║ CD  ( as AB ║ CD & E lies on AB)

=>  Area of ΔACE  = Area of  ΔADE

Equating both

Area of  ΔACF =Area of  ΔADE

=> Area of  ΔADE = Area of  ΔACF