17 a uniform rod of mass m and length l is lying on a smooth horizontal table. The work done by external agent in slowly making it stand vertical on one end is
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Answer:
THE POTENTTIAL ENERGY =WORK DONE IN
RISING IT FROM HORIZONTAL POSTION TO VERTICAL POSTION.
DOING THIS,THE MID POINT OF THE ROD IS RAISED THROUGH A HEIGHT H=L/2.SINCE THE ENTIRE MASS OF THE ROD CAN BE ASSUMED TO BE CONCENTRATED AT MIDPOINT(CENTER OF GRAVITY),
WD=MGH=MGL/2
THEREFORE
PE=MGL/2
Explanation:
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