Question

17. A wooden block of mass 10 kg pushed up a rough inclined plane at a constant speed by a force of 50 N. When the block travels from X to Y, it reaches a height of 5 m and travels a distance of 13 m along the plane, then what is the work done against friction?
A. 650 J
B. 600 J
C. 250 J
D. 150 J

Answer 1

answer : option (D) 150 J

mass of wooden block, m = 10kg

let angle of inclination is θ

as block is pushed up with constant speed on rough inclined plane.

so, friction force must be equal to force applied on it.

change in kinetic energy = 0

change in potential energy , U = mgh

= 10kg × 10m/s² × 5m

= 500 J

workdone on the block due to applied force on the plane, W1 = 50N × 13m = 650 J

as

from conservation of work- energy theorem,

total workdone on the block to move upward = potential energy + workdone against friction.

⇒650 J = 500J + workdone against friction

⇒ workdone against friction = 150 J

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Answer 2

$\huge\bold\purple{Answer:-}$

D. 150 J