Question

17) ABCD is a square of 20 m. What is the area of the least-sized square that
can be inscribed in it with its vertices on the sides of ABCD?
(a) 120 (b) 100 (C) 200 (d) 250 (e) None​

Answer 1

Answer:

C. 200

Step-by-step explanation:

The smallest square that can be inscribed will be formed by joining the center point of all the sides os square ABCD

Hence, now the figure will be like the image above.

Now, u can find the side of PQRS by Pythagoras theorem

$\sqrt{ {10}^{2} + {10}^{2} } = \sqrt{200}$

Now square PQRS is of side √200

Now finds it's area by formula,

A=s^2

Area will become 200

Answer 2

Answer:

200

step-by-step explanation:

The area of the square is = a^2+a^2

in the above given ABCD=20m

in square all side are equal to each other

so 20×20+20×20=800

800/4 equal parts is 200