Question

17.
Calculate the number of moles of HCl required to
neutrilize 0.5 mol of Al(OH), solution ?​

Answer 1

Answer:

0.5

Explanation:

as NF is 1 in both the compounds

Answer 2

Answer:

       1.5 mol of HCl

Explanation:

3HCl + Al(OH)₃ ⇒ AlCl₃ + 3H₂O

1 mol of Al(OH)₃ ≡ 3 mol of HCl

0.5 mol of Al(OH)₃ ≡ 0.5 × 3 mol of HCl

                               ≡ 1.5 mol of HCl