Question

fi n=2 find the value of the all four quantam number​

Answer 1

Answer:

if n=2

1=0 to (n-1)=0, (2-1)=0,1 where 0 is s orbital and 1 is p orbital. therefore there are 2 values for 1

m on the other hand, depends on 1 where for n=2 , we found that 1=2

therefore 2.1+1=2(2)+1=5

orientation= -2,-1,0,+1,+2

to sum where n=2, 1=2 [0,1] ,m=5 [-2,-1,0,+1,+2]

HOPE ITS HELP U!!!