17 card numberef 1,2,3...........16,17 are put ina box and mixed thoroughly .one person draws a card from the box .find the probability that the number on the card is a) a prime number b)divisible by 3
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here you go ☆☆
probability = no. of possible outcome /total outcomes
total cards = 17
▪A. no. of prime no. = 7 (2, 3, 5, 7, 11, 13, 17)
p ( getting prime no. ) = 7/17
▪B.no. divisible by 3= 5 ( 3, 6, 9, 12, 15)
p ( getting no. divisible by 3 ) = 5/15
hope it helps you....
probability = no. of possible outcome /total outcomes
total cards = 17
▪A. no. of prime no. = 7 (2, 3, 5, 7, 11, 13, 17)
p ( getting prime no. ) = 7/17
▪B.no. divisible by 3= 5 ( 3, 6, 9, 12, 15)
p ( getting no. divisible by 3 ) = 5/15
hope it helps you....
ShadowLucifer:
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Answered by
11
Here is the answer....
*a) total no. Of cards =17
No. Of cards with prime no.s = cards of 2, 3, 5, 7, 11, 13, 17 =7 cards in total
So, the probability of getting a card with prime no. =7/17
*b) total no. Of numbers divisible by three = 3, 6, 9, 12, 15 = 5 no. s
So no. Of cards with numbers divisible by three =5/17
Hope it helped you.....
P.S. Please mark it as brainliest
*a) total no. Of cards =17
No. Of cards with prime no.s = cards of 2, 3, 5, 7, 11, 13, 17 =7 cards in total
So, the probability of getting a card with prime no. =7/17
*b) total no. Of numbers divisible by three = 3, 6, 9, 12, 15 = 5 no. s
So no. Of cards with numbers divisible by three =5/17
Hope it helped you.....
P.S. Please mark it as brainliest
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