17. Construct a triangle ABC in which 2A = 120° and AB = AC = 5cm . Draw the bisector of angle
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Hello dear,
The steps for the construction above are as follows:-
1. Draw BC = 5 cm and construct angle B = 120° ( either with protractor or compass, I have done using a compass).
2. Cut the ray of angle B at A with an arc of 4 cm. Join AC.
3. Draw ray BX such that angle CBX is an acute angle.
4. Cut the ray BX in 5 parts of equal length.
5. Name them as B1, B2, B3, B4 and B5. Join CB5.
6. Through B4, draw a line parallel to CB5 which intersects BC at C'.
7. Through C', draw another line parallel to AC which intersects AB at A'.
8. ∆A'BC' is the required triangle.
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