Question

17. Divide the product of 4x2 – 9 and 2x2 – 3x + 1 by
4x3 – 7x + 3​

Answer 1

product of 4x^2-9& 2x^2-3x+1 is

(4x^2-9)(2x^2-3x+1)=8x^4-12x^3+4x^2-18x^2+27x-9

=8x^4-12x^3-14x^2+27x-9

diving 8x^4-12x^3-14x^2+27x-9 by 4x^3-7x+3

4x^3-7x+3)8x^4-12x^3-14x^2+27x-9(2x-3

8x^4-14x^2+6x

_______________________

-12x^3+21x-9

-12x^3+21x-9

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0