Question

17. Factorise, x2 – 2ab + 2ax – bx​

Answer 1

SOLUTION:-

→ x²-2ab+2ax-bx=0

→ x²+2ax-2ab-bx=0

→ x (x+2a)-b(2a+x)=0

→ (x+2a)(x-b)=0

→ x+2a=0 and x-b=0

→ x=-2a and x=b

Hence, the two factors of the given equation are -2a and b.

I hope this will help you friend.

Answer 2

Given:-

• x² – 2ab + 2ax – bx

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To find:-

• Factorise the following.

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Solution:-

According to the question

→ x² - 2ab + 2ax - bx

→ x² + 2ax - 2ab - bx

→ x(x + 2a) - b(2a + x)

→ (x + 2a) (x - b)

→ x + 2a and x - b

→ x =- 2a and x = b

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Hence,

• the two factors of the given equation are -2a and b.