Math, asked by manishkumar4321hajip, 6 months ago

17. Find the smallest square number, that is divisible by each of the numbers 8, 15 and 20.

Answers

Answered by s9890
0

Answer:

Go ask google

Step-by-step explanation:

Hope it helps you

Hahah

Answered by harshithasinghthakur
1

Answer:

3600

Step-by-step explanation:

The number that is perfectly divisible by each of the numbers 8, 15, and 20 is their LCM.

2 {8, 15, 20}

2 {4, 15, 10}

2 {2, 15, 5}

3 {1, 15, 5}

5 {1, 5, 5}

{ 1, 1, 1}

LCM of 8, 15, and 20 = 2 × 2 × 2 × 3 × 5 =120

Here, prime factors 2, 3, and 5 do not have their respective pairs. Therefore, 120 is not a perfect square.

Therefore, 120 should be multiplied by 2 × 3 × 5, i.e. 30, to obtain a perfect square.

Hence, the required square number is 120 × 2 × 3 × 5 = 3600.

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Hope it helps!(◕ᴗ◕✿)

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