Question

17. Focus of the parabola y2 = 8x is​

Answer 1

Correct option is

A

(x−2)

2

+y

2

=9

y

2

=8x

This eqn. is of the form

y

2

=4ax⇒4a=8

a=2

∴ Its focus S is (2,0).

Clearly the points P and Q

are points of intersection of

y

2

=8x and x

2

+y

2

−2x−4y=0

 ↓                            ↓

(1)                          (2)

Now we solve (1) and (2) to

find p and Q