Question

17. How many digits are there in the expression 6^2 x 2^98 5^99?
(a) 103
(b)102
(c) 101
0) 100​

Answer 1

Answer:

Option C is correct.

Step-by-step explanation:

Given Expression:

$6^2\times2^{98}\times5^{99}$

To find: Number of digits in the expression

Consider,

$6^2\times2^{98}\times5^{99}$

$=6^2\times2^{98}\times5^{98+1}$

$=6^2\times2^{98}\times5^{98}\times5^1$

$=6^2\times5^1\times(2\times5)^{98}$

$=36\times5\times(10)^{98}$

$=180\times(10)^{98}$

So, Total number of digits in the expression is 101

Therefore, Option C is correct.

Answer 2

Answer:

c, 101 is the answer which is correct