Question

17. I. 6x² + 5x + 1 = 0
II. 3y -8y - 3 = 0​

Answer 1

Hi there!

6x² + 5x + 1 = 0

$=6 {x}^{2} + 2x + 3x + 1 \\ \\ = 2x(3x + 1) + 1(3x + 1) \\ \\ = (3x + 1)(2x + 1) \\ \\ = x = \frac{ - 1}{3} \: \: and \: \frac{ - 1}{2}$

2) 3y-8y-3=0

= -5y = 3

= y= -3/5

Thankyou :)