Question

17. If C is the midpoint of AB and P is any point outside AB, then a) PA + PB = 2 PC b) PA + PB = PC c) PA + PB + 2 PC = 0 d) PA + PB + PC = 0​

Answer 1

Answer:

PA=PC+CA

PB=PC+CB

PA+PB=2PC+(CA+CB)

=2PC       (∵CA=−CB)

Hence CA+CB=0 

and PA+PB=2PC