17) In AABC, DE//BC, then find x if AD=X, AE=X+3. C=X+5 and BD=x+1.
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in triangle ABC
DE//BC and AD=x=?
is given AE=x+3, EC=x+5, DB=x+1 and AD=x.
in triangle ABC and ADF
DE//BC.
angle ADE =angle ABC and angle AFD= angle ACB.
Triangle ABC~ Triangle ADF
AB/AD=AE/AC=BC/DE
AB=x+x+1=2x+1, AC=x+3+x+5=2x+8,
AD=x, AE=x+3.
AB/AD=AC/AE
2x+1/x=2x+8/x+3.
(2x+1)(x+3)=x(2x+8)
2x^2+7x+3=2x^2+8x
8x-7x=3
x=3. Answer
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