Question

17. In the given figure, angle DAB = angle CBA,
AD = BC. Prove triange ADB is congruent to triangle BCA.​

Answer 1

Answer:

In triangles ABD and BAC, we have

AD=BC (given);

AB=AB (common);

AC=BD (given).

We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that

∠ADB=∠BCA and ∠DAB=∠CBA.

HENCE PROVED .

Answer 2

Answer:

Step-by-step explanation:

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