17. It is found, on heating a gas, its volume increases by 50%
and pressure decreases to 60% of its original value. If the
onginal temperature was -15°C, find the temperature to
which it was heated ?
[Ans.-40.8°C]
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Answer:
Answer
Let the original volume (V)=1 and
the original pressure (P)=1 and
the temperature given (T)=−15
∘
C=−15+273=258K
V
1
or new volume after heating = original volume +50% of original volume
1+1×
100
50
=1+
2
1
=
2
3
Here P
1
is the decreased pressure
P
1
=60%
=
100
1×60
=0.6
T1=?
T
PV
=
T
1
P
1
V
1
258
1×1
=
2
3
×
T
1
0.6
T
1
=232.2K
T
1
=232.2−273
=−40.8 °c
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