Question

17. los
(1) log10 (x + 1) + log10 (x - 1)
log 10 11 +2 logo3
​

Answer 1

Answer:

here is your answer.......

Step-by-step explanation:

If this is the problem........log10(x+2) + log10(x) - 1 = log10(1.5)

Then log10{(x+2)(x)} - 1 = log10(1.5)

Then log10{(x+2)(x)} - log10(1.5) = 1 or log10{(x+2)(x)/(1.5)} = 1

Take each side to the 10th power to get

(x+2)(x)/(1.5) =101 then (x+2)(x) =15 or x2 + 2x = 15 or x2+2x -15 = 0

This factors to (x+5)(x-3) = 0. So x = -5 & 3

The problems is that you cannot take the log of a negative number so 3 is the only realistic solution!

Answer 2

Answer:

If this is the problem........log10(x+2) + log10(x) - 1 = log10(1.5)

Then log10{(x+2)(x)} - 1 = log10(1.5)

Then log10{(x+2)(x)} - log10(1.5) = 1 or log10{(x+2)(x)/(1.5)} = 1

Take each side to the 10th power to get

(x+2)(x)/(1.5) =101 then (x+2)(x) =15 or x2 + 2x = 15 or x2+2x -15 = 0

This factors to (x+5)(x-3) = 0. So x = -5 & 3

The problems is that you cannot take the log of a negative number so 3 is the only realistic solution!