17)
O is the centre of the circle, AB is a chord of the circle. OM I AB. If AB = 20 cm, OM = 2√11 cm, then
radius of the circle is -
(1) 15 cm
(2) 12 cm
(3) 10 cm
(4) 11 cm
Answers
Answered by
11
Answer:
12
Step-by-step explanation:
om square + half of ab square =. ob square (r)
2√11 square + 10 square = r square
=44+100=r square
144=r square
r=12
Answered by
1
Step-by-step explanation:
I am assuming I om to be parallel to ab .
when you elongate a b and o m they both would pass through the centre
ab half and om half become sides of triangle.angle subtended in a semicircle is equal to 90° .by Pythagoras theorem
(20)(20)=(44)(x)(x). the radius of the circle would be 10 centimetres
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