Math, asked by Dhruv2019, 10 months ago

17)
O is the centre of the circle, AB is a chord of the circle. OM I AB. If AB = 20 cm, OM = 2√11 cm, then
radius of the circle is -
(1) 15 cm
(2) 12 cm
(3) 10 cm
(4) 11 cm

Answers

Answered by vishal241244
11

Answer:

12

Step-by-step explanation:

om square + half of ab square =. ob square (r)

2√11 square + 10 square = r square

=44+100=r square

144=r square

r=12

Answered by Vaishnavi243
1

Step-by-step explanation:

I am assuming I om to be parallel to ab .

when you elongate a b and o m they both would pass through the centre

ab half and om half become sides of triangle.angle subtended in a semicircle is equal to 90° .by Pythagoras theorem

(20)(20)=(44)(x)(x). the radius of the circle would be 10 centimetres

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