Question

The flo
or of a rectangular room has length 4 m and breadth 3.2 m. Find the number of tiles required to cover
the floor, if each side of a tile measures 40 cm.​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore No.\:of\:tiles=80}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information giveb about a floor of a rectangular room has length 4 m and breadth 3.2 m.

• We have to Find the number of tiles required to cover the floor, if each side of a tile measures 40 cm.

$\underline \bold{Given : } \\ \implies Length = 4 \: m \\ \\ \implies Breadth = 3.2 \: m \\ \\ \implies Side \: of \: tile = 40 \:cm\\ \\\underline \bold{To \: Find : } \\ \implies No. \: of \:tiles = ?$

• According to given question :

$\bold{Using \: formula \: of \: area \: of \: rectangle : } \\ \implies area \: of \: room =L \times B \\ \\ \implies Area_{1} = 4 \times 3.2 \\ \\ \bold{\implies Area_{1} = 12.8 \: {m}^{2} } \\ \\ \bold{Using \: formula \: of \: area \: of \: square : } \\ \implies Area \: of \: tile = {side}^{2} \\ \\ \implies Area_{2} = {40}^{2} \\ \\ \implies Area_{2} = 1600 \: {cm}^{2} \\ \\ \bold{For \: no. \: of \: tile : } \\ \implies No. \: of \: tile = \frac{ Area_{1}}{ Area_{2}} \\ \\ \implies No. \: of \: tile = \frac{12.8 {m}^{2} }{1600 { cm}^{2} } \\ \\ \implies No. \: of \: tile = \frac{\cancel{128000}}{\cancel{1600}} \\ \\ \bold{\implies No. \: of \: tiles =80}$

Answer 2

Answer:

• No. of tiles = 80

Step-by-step explanation:

$\to no. \: of \: tiles = \frac{area \: of \: room}{area \: of \: one \: tile} \\ \\ \to no. \: of \: tile = \frac{(4 \times 3.2)m}{40 \: cm} \\ \\ \implies no. \: of \: tile = \frac{400 \times 320}{40} \\ \\ \bold{\to no. \: of \: tile = 80 \: tiles}$