Question

17. Renaldo catches the bus at 4:00 P.M. to ride 3.2 miles from his house to the dentist’s office. He arrives at 4:30 P.M., for a one-hour appointment. Then he will ride a bus traveling at the same rate of speed for 4.8 miles to the soccer field. Will he be on time for his 6:30 P.M. soccer practice?

Answer 1

Answer:

Renaldo catches the bus at 4:00 P.M. to ride 3.2 miles from his house to the dentist’s office. He arrives at 4:30 P.M., for a one-hour appointment. Then he will ride a bus traveling at the same rate of speed for 4.8 miles to the soccer field. Will he be on time for his 6:30 P.M. soccer practiceRenaldo catches the bus at 4:00 P.M. to ride 3.2 miles from his house to the dentist’s office. He arrives at 4:30 P.M., for a one-hour appointment. Then he will ride a bus traveling at the same rate of speed for 4.8 miles to the soccer field. Will he be on time for his 6:30 P.M. soccer practiceRenaldo catches the bus at 4:00 P.M. to ride 3.2 miles from his house to the dentist’s office. He arrives at 4:30 P.M., for a one-hour appointment. Then he will ride a bus traveling at the same rate of speed for 4.8 miles to the soccer field. Will he be on time for his 6:30 P.M. soccer practiceRenaldo catches the bus at 4:00 P.M. to ride 3.2 miles from his house to the dentist’s office. He arrives at 4:30 P.M., for a one-hour appointment. Then he will ride a bus traveling at the same rate of speed for 4.8 miles to the soccer field. Will he be on time for his 6:30 P.M. soccer practice?

Answer 2

No he will be at soccer field at 6:50 approx since the total duration can be calculated as follows : 4:30 at dentist office , 1 hour appointment makes it 5:30 , speed is given by 3.2/.5 = 6.4Miles/hr so the time taken to cover 4.8 miles would be 6.4/4.8 Hrs which is Approx 1 Hr 20 min so if he starts at 5:30 from dentists office it would take him 1 Hr 20 min to reach soccer field which would be Approx 6:50 So he’s probably late by 15-20 min