Question

17 Solve sin 2x - sin4x +sin6x =0

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Answer 1

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Answer 2

explanation :

sin2x-sin4x+sin6x=0

(sin2x+sin6x) - sin4x =0

2sin{2x+6x/2} cos{2x-6x/2} - sin4x=0

2sin4x cos2x-sin4x=0

sin4x(2cos2x-1)=0

sin4x=0 cos2x=1/2

4x= n

$4x = n\pi$

$x = n\pi \div 4$

$2x = 2n \pi + - \pi \div 3$

$x = n\pi + - \pi \div 6$

Here is your answer.......

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