17. The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio
7:8:9. Their present ages are
Answers
Let the rational between ages of three persons 10 years ago was x
Ten years ago, their ages were in the ratio of 7:8:9.
Thus their ages were 7x, 8x and 9x
Their present ages 7x + 10, 8x + 10 and 9x + 10
The sum of the ages of 3 persons is 150 years. Accordingly
7x + 10 + 8x + 10 + 9x + 10 = 150
24x + 30 = 150
24x = 150 - 30
24x = 120
x = 120/24
x = 5
The rational is 5. Their ages 10 years ago,
1st person 7x = 7 × 5 = 35 years
2nd person 8x = 8 × 5 = 40 years
3rd person 9x = 9 × 5 = 45 years
Their present ages
1st person = 35 years + 10 years = 45 years
2nd person = 40 years + 10 years = 50 years
3rd person = 45 years + 10 years = 55 ,hears
Answer the present ages of three persons are 45 years, 50 years and 55 year's
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Answer:
45,50,55
Step-by-step explanation:
150-30= 120
120/ (7+8+9)
120/24 =5
(5*7 + 10) + (5*8+10) +(5*9+10) = 150
45+50+55= 150