Question

A cistern has a leak which would empty it in 6 hours. A tap is turned on which fills the cistern @ 10 liters per hour and when the tank is full then it is emptied in 15 hours(when tap and the leak are active). What is the capacity of the cistern

Answer 1

Answer:

Step-by-step explanation:

Part filled in 1 hours = (1/6 - 1/15) = 1/10

Therefore Time taken to fill the cistern = 10 hours

Water moved in 10 hours = (10×10×60) litres = 6000 litres

Hope it helps you....

Answer 2

Answer :

Let leak ( outlet) is A 6 hours to empty.

B inlet is let x

AB can empty in 15 hours. ( both are in active)

so for 1 hour A can empty ( 1/6) *30 = -5 ( Empty)

lly AB can finish work for 1 hour = (1/15) *30 =-2( Empty).

for B inlet is 30/3 = 10hrs . i. e for 1 hour it can fill 10 lts then for 10 hr it can fill whole take = 10*10 = 100 L