A compound containing sulphur and oxygen on analysis reveals that it contains 50.1% sulphur and 49.9% oxygen by mass. What is the simplest formula of the compound?
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S 50.1% 32 50.1÷32=1.5(apprx) 1.56÷1.56=1
O 49.9% 16 49.9÷16= 3 (apprx) 3÷1.5=2
answer:SO2
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Here is your answer buddy
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