Question

17. Two numbers differ by 40. When each
number is increased by 8, the bigger
becomes thrice the lesser number. If one
number is x, then the other number is​

Answer 1

To Find:-

• Find the bigger and the smaller number.

Given:-

• Let the bigger number = x
• The smaller number be 40 - x
• If each number is increased by 8 then

️ ➭ Bigger number = x + 8

️ ➭ Smaller number = 40 - x + 8

️ ➭ 48 - x

So,

The equation is x + 8 = 3( 48 - x )

️ ➭ x + 8 = 144 - 3x

️ ➭ 3x + x = 144 - 8

️ ➭ 4x = 136

️ ➭ $\tt { \boxed{ \: x \: = \: 34 \:} }$

So,

Bigger number = 34

Smaller number = 14

Verification:-

️ ➭ x + 8 = 144 - 3x

️ ➭ 34 + 8 = 144 -3(34)

️ ➭ 42 = 144 - 102

️ ➭ $\tt { \boxed{ \: 42 \: = \: 42 \:} }$

Answer 2

Answer:

Given :-

• Difference of two numbers is 40
• When both number increased by 8 then the bigger become thrice of smaller.
• One number = x

To Find :-

The number

Solution :-

Let the bigger number be x

Bigger number = x + 8

Smaller number = 40 - x + 8 = 48 - x

x + 8 = 144 - 3x

️ 3x + x = 144 - 8

️ 4x = 136

️

$\boxed{\bf{ \: x \: = \: 34 \:}}$

Bigger number = 34

Smaller number =34-20 = 14