Question

1723*4 In each of the following numbers, replace*by the smallest number to make it divisible by 11

Answer 1

Answer:

So first we have to know the divisibility test of 11.

If the alternate numbers from right to left are added as in the above number

 we will add 1+2+(no.we have to find=x)

                   3+x

And other alternate numbers as 7+3+4=14

So the rule is that when you subtract the first list of alternate numbers from the second list, the difference should be 0 or a multiple of 11.

So 3+x-14=0[As we have to find the smallest number]

    3+x=14

    x=14-3 

    x=11

Because the number is equal by 11 we will subtract 11 from the number.

11-11=0

Therefore the smallest number is 0.

Step-by-step explanation:

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Answer 2

Answer: The smallest number or the missing digit in 1723*4 is 0

Step-by-step explanation:

1723*4

Let the missing digit be x. So first we should know the divisibility test of 11.

First we add the alternate digits from right to left in 1723*4

So we will add 1+2+x = 3+x --------- (1)

And other alternate digits in 1723*4  as 7+3+4=14   ---------- (2)

So the rule is that when we subtract the first list of alternate digits from the second list, the difference must be 0 or a multiple of 11.

Now,
⇒ 3+x-14=0  

⇒ 3+x=14

⇒  x=14-3

 ∴ x=11

Since the number is equal to 11 we will subtract 11 from the number.

11-11=0 (it is given that we have to find the smallest number)

Therefore, the smallest number or the missing digit in 1723*4 is 0 .

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