Question

177 Find the roots of the following
quadratle equation Poinsula

$2 {x}^{2} - 2 \sqrt{2x} + 1 = 0$
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Answer 1

Answer:

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Answer 2

Answer:

$\frac{1}{ \sqrt{2} }$

Step-by-step explanation:

$2 {x}^{2} - 2 \sqrt{2} x + 1 = 0$

$2 {x}^{2} - \sqrt{2} x - \sqrt{2} x + 1 = 0$

$\sqrt{2}x ( \sqrt{2} {x} - 1) - 1( \sqrt{2} x- 1) = 0$

$( \sqrt{2} x - 1)( \sqrt{2} x - 1) = 0$

$x = \frac{1}{ \sqrt{2} } \: \: \frac{1}{ \sqrt{2} }$