Question

17th term of an ap exceeds its 10th term by 14 then find the common difference

Answer 1

a^17 -a^10 = 14
a +16d -a -9d = 14
a remove with a bcoz they have opposite sign in same side so it is remove,,.....
7d = 14
d =2
so, the common difference is 2.

Answer 2

GIVEN
17th term of an ap exceeds its 10th term by 14 then find the common difference
a17 = a10 + 14
a + 16d = a + 9d + 14
a - a + 16d - 9d = 14
7d = 14
d = 14 / 7
d = 2
Therefore, the common difference 'd' is 2.