Question

18,000 for 2,1/2 years at 10% per annum compounded annually.

Answer 1

Answer:

$Compound \: Interest = Rs \: 4869$

Step-by-step explanation:

$i) Principal (P) = Rs\:18000 ,\\Time (T) = 2 \: years ,\\Rate \: of \: interest (r) = 10%, \\number \: of \: times \: Interest \: paid (n) = 2$

$\boxed { \pink { Amount (A) = P\left( 1 + \frac{r}{100}\right)^{n} }}$

$A = 18000 \left( 1 + \frac{10}{100}\right)^{2}\\= 18000 \times ( 1.1)^{2} \\= Rs\:21780$

$Compound \: Interest \:for \: 2 \: years\\ = A - P\\= Rs \: 21780 - Rs \: 18000 \\= Rs\: 3780 \: ---(1)$

$Now, principal \:for \: next \: 6\: months = A = Rs\:21780 , \\Time (T) = \frac{1}{2} \: years ,\\Rate \:of \: Interest (R) = 10\%$

$Simple \: Interest (I) = \frac{PTR}{100}\\= \frac{ 21780\times \frac{1}{2} \times 10}{100}\\= Rs\:1089 \: ---(2)$

$Total \: Interest = Rs \: 3780 + Rs \: 1089\\= Rs\:4869$

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Answer 2

Step-by-step explanation:

Amount =18000(1+10100)2=18000(1+10100)2

=18000×1110×1110=21780=18000×1110×1110=21780

Interest after 2 years =21780−18000=3780=21780-18000=3780

Interest after half year =21780×10100×12=1089=21780×10100×12=1089

Total interest after 2.5 years =3780+1089=4869