Question

18. A bag contains 5 red, 6 green and 7
yellow balls. One ball is taken out from the
bag at random. The probability of getting a
non-green ball is
O
6
O
12
O 1/3
O 2/3.​

Answer 1

EXPLANATION.

→ A bag containing 5 red balls, 6 green balls,

7 yellow balls,.

→ One ball is taken out from the bag at random.

→ Probability of getting a non - green ball.

→ Total number of balls in a bag.

→ 5 red + 6 green + 7 yellow = 18 balls.

→ Non - green balls = 5 red + 7 yellow =

12 balls.

→ Non - green balls / Total number of Balls.

→ 12/18 = 2/3

→ Probability of getting non - green

balls = 2/3.

→ Option [ D ] is correct answer.

Answer 2

Answer:

⠀⠀ ⌬ Red Balls = 5

⠀⠀ ⌬ Green Balls = 6

⠀⠀ ⌬ Yellow Balls = 7

• Outcome of Green Balls :

$:\implies\sf Probability(Green)=\dfrac{Green\:Outcomes}{Total\:Outcomes}\\\\\\:\implies\sf P(G)=\dfrac{6}{5+6+7}\\\\\\:\implies\sf P(G) = \dfrac{6}{18}\\\\\\:\implies\sf P(G) =\dfrac{1}{3}$

$\rule{180}{1.5}$

• Outcome of Non Green Balls :

• we know that Probability will fall in between 0 to 1. Hence

$:\implies\sf P(Non-Green)+P(Green)=1\\\\\\:\implies\sf P(NG) + \dfrac{1}{3} = 1\\\\\\:\implies\sf P(NG) = 1 - \dfrac{1}{3}\\\\\\:\implies\sf P(NG) = \dfrac{3 - 1}{3}\\\\\\:\implies\underline{\boxed{\sf P(NG) = \dfrac{2}{3} }}$

⠀

$\therefore\:\underline{\textsf{Probability of getting Non Green is d) \textbf{ \dfrac{\text2}{\text3} }}}$