Question

18. A body is projected with the speed v at
an angle of 45° with
respect to the Earth. What is the time of
flight of the body?
v/g
V2v/g
v*v/g
2v*v/g​

Answer 1

Answer:

ans will be √2v/g

Explanation:

time of flight= 2usin theta/g

u=v, sin 45=1/√2

time= 2v/√2g ,by rationalising we will get √2v/g