Question

18. A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random
from the box, find the probability that it bears (i) a two-digit number (ii) a perfect
square number (iii) a number divisible by 5.​

Answer 1

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1) P ( 2-digit no. ) = 81/90 = 67/30

2) P ( a perfect square ) = 9/90 = 1/10

3) P ( number divisible by 5 ) = 18/90 = 1/5

Answer 2

answer -

1. P ( 2-digit no. ) = 81/90 = 67/30

2) P ( a perfect square ) = 9/90 = 1/10

3) P ( number divisible by 5 ) = 18/90 = 1/5