Question

18. A car starting from rest picks up a velocity of 36km/hr over a distance of 50 m. Calculate its acceleration​

Answer 1

Answer:

$\tt {\pink{Given:}}$

• Initial velocity (u) = 0ms⁻¹.
• Final velocity (v) = 36kmhr⁻¹ ⇒ 10ms⁻¹
• Distance (s) = 50 m

$\tt {\pink{SOLUTION:}}$

We know that:

$\tt {\blue{2as=v^2-u^2}}$

$\tt 2 \times a \times 50 = 10^2-0^2$

$\tt 100a=100$

$\tt a= \frac{100}{100}$

$\tt a=1 ms^{-2}$

HOPE THIS HELPS :D