* 18. A liquid mixture is prepared by mixing liquids A and
B having vapour pressure 250 mm Hg and 330 mm
Hg respectively. If the mole fraction of A in the
solution is 0.6, what is the mole fraction of B in
vapour phase ?
(Ans. YB = 0.47)
Answers
Answered by
2
Answer:
P
total
=X
A
.P
A
0
+X
B
.P
B
0
=0.5×400+0.5×600=500mmHg
Now, mole fraction of A in vapour,
Y
A
=
P
total
P
A
=
500
0.5×400
=0.4
and mole fraction of B in vapour,
Y
B
=1−0.4=0.6
Similar questions