Question

18.
A stone tied to the end of a string 2 m
long is whirled horizontal circle with
constant speed. If the stone makes 10
revolutions in 20 seconds. Calculate
the magnitude and direction of
acceleration.
10​

Answer 1

Length of string ( radius ) = 2 m

revolutions made = 10

time taken = 20 s

distance travelled = circumference × revolutions

                              = 2 × $\frac{22}{7}$ × 2 × 10

                              = 125.714 m

magnitude will be N.A as the stone will be moving in a circular direction.

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