Question

18.A vessel contains water up to a height of 5.5 m. Taking the density of
water as 1000 kilogram/cubic metre, and acceleration due to gravity as 9.8
metre/second square, the pressure exerted at the base of the vessel
newton/metre square. *
is.............
O 5.39
O539
O53900​

Answer 1

Answer:Pressure is given by:

P = hρg

where h is the height or depth of the liquid

ρ is the density of the liquid

g = acceleration due to gravity = 9.8 m/s^2

= 980 cm/s^2

h = 1.5 m

ρ = 1000 kg/m^3

P = 1.5 × 1000 × 9.8

P = 14700 pa

pressue = force/area

thrust = force = pressure × area

= 14700 × 100 × 10^−4

= 147 N

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