Question

18. A woman walks a certain distance in 84 min. She covers two thirds of It al 4 kmh and the
rest at 5 km/h. Find the total distance she covered​

Answer 1

Given women walk a certain distance in 84 minutes in the first two-thirds of the time she walked at 4 km ph

So distance covered in 1

st

two-third is

x=4kmph×

3

2

×84 min

=4×

3

2

×

60

84

hr

x=3.733 km

So remaining distance is

y=5×

3

1

×

60

84

=2.333 km

∴ Total distance =x+y=6.067 km