18. Calculate 'x' in the given figure, where PA and PB are tangent
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∠A+∠B+∠O+∠P=180
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Answer:
<OAP=<OBP=90°[The radius of the tangent and the tangent to the tangent are perpendicular to each other.]
OABP is a Quadrilateral then,
130°+90°+90°+2x=360°[The sum of the four angles of the quadrilateral is 360 degrees]
- 2x=360-310
- x=50/2
- x=25
The value of x is 25° .
Hope you understand
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