Question

18) Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts the x-axis and the y-axis?

Answer 1

Your Answer:

Given:-

Linear Equation of the Graph as 3x + 4y = 6

Solution:-

Finding points to plot

3x + 4y = 6

For the first point

Let x = 2

So,

$\tt 3(2) + 4y = 6 \\\\ \tt \Rightarrow 6 + 4y = 6 \\\\ \tt \Rightarrow 4y = 0 \\\\ \tt \Rightarrow y=0$

So,the first point is A(2,0)

For the second point

Let x = 6

So,

$\tt 3(6) +4y = 6 \\\\ \tt \Rightarrow 18 +4y =6 \\\\ \tt \Rightarrow 4y = -12 \\\\ \tt \Rightarrow y = -3$

So, the second point is B(6,-3)

So, by observing the graph we come to know that

linear Equation Graph cuts the x axis at (2,0) and y axis at (0, 3/2)