Question

18. If Garland is to be placed along the side of triangle QPR which is formed 1 point
by joining mid points, then the length of garland is: A) 79 cm B) 39.5 cm C)
35 cm D) 79.5 cm​

Answer 1

Answer:

39.5 cm

Step-by-step explanation:

14+13+12.5

=27+12.5

=39.5cm

Answer 2

Answer:

Length of garland $=39.5cm$

Step-by-step explanation:

Given, dimensions of Δ$ABC$ are $AB = 25cm, BC = 28cm$ and $CA = 26 cm.$

In Δ$ABC, R$ and $Q$ are the mid-points of sides $AB$ and $AC$, respectively.

Since, $R$ and $Q$ are the mid-points of $AB$ and $CA,$ respectively.

$RQ$║$BC$ and $RQ=\frac{1}{2}BC$ [by mid-point theorem]

⇒ $RQ=\frac{1}{2}*28=14cm$

similarly, $P$ and $Q$ are the mid-points of $BC$ and $AC,$ respectively.

$QP$║$AB$ and $QP=\frac{1}{2} AB$ [by mid-point theorem]

⇒ $QP=\frac{1}{2}*AB=\frac{1}{2}*25=12.5cm$

and $P$ and $R$ are the mid-points of $BC$ and $AB$, respectively.

$PR$ ║$AC$ and $PR=\frac{1}{2}AC$ [by mid-point theorem]

⇒ $PR=\frac{1}{2}*AC=\frac{1}{2}*26=13cm$

Length of garland $=$ Perimeter of Δ$PQR$

                              $=RQ+QR+PR$

                              $=14+12.5+13=39.5cm$