Question

factorise using identities​

Answer 1

Answer:

$(i) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4 {p}^{2} - 9 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {2p}^{2} - {3}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2p + 3)(2p - 3)$

${4x}^{2} - 169 {y}^{2} \\ = {(2x)}^{2} - {(13y) }^{2} \\ = (2x + 13y)(2x - 13y)$

$9 {x}^{2} {y}^{2} - 25 \\ = {(3xy)}^{2} - {5}^{2} \\ = (3xy + 5)(3xy - 5)$

$16 {x}^{2} - \frac{1}{144} \\ = {(4x)}^{2} - {( \frac{1}{12} )}^{2} \\ = (4x + \frac{1}{12} )(4x - \frac{1}{12} )$

$\frac{9}{16} - 25 {a}^{2} {b}^{2} \\ = {( \frac{3}{4} )}^{2} - {(5ab)}^{2} \\ = ( \frac{3}{4} + 5ab)( \frac{3}{4} - 5ab)$