Question

18. If (x + p) is a factor of x^2+ px +3 - p is equal to
a)1
b)-1
c)3
d)-3



The first answer will be marked as brainliest​

Answer 1

Answer:

Option C is correct.

Step-by-step explanation:

Using Factor Theorem.

Let f( x ) = x^2 + px + 3 - p. ... ( 1 )

Putting x = p in ( 1 ), we get

= > f( - p )

= > ( - p )^2 + p( - p ) + 3 - p = 0

= > p^2 - p^2 + 3 - p = 0

= > 3 - p = 0

= > 3 = p

Therefore,

By corollary 1 to factor theorem, ( x + p ) is a factor of x^2 + px + 3 - p.

Hence the required value of p is 3.

Option C is correct.

Answer 2

(x + p) is a factor of x² + px + 3 - p

_______ [GIVEN EQUATION]

According to question (x + p if factor of equation x² + px + 3 - p.

Here (x + p) is remainder of the given equation.

So

• x + p = 0

=> x = - p _____ (eq 1)

» Put value of x in x² + px - 3 - p

=> (-p)² + p (-p) + 3 - p = 0

=> p² - p² + 3 - p = 0

=> 3 - p = 0

=> p = 3

____________________________

If (x + p) is a factor of x²+ px + 3 - p. Then p = 3

So, correct option is c) 3

_________ [ANSWER]

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✡ More information :

• (-) (-) = +

• (+) (+) = +

• (-) (+) = -

• (+) (-) = +

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