Math, asked by rajranisnahi, 1 year ago

18- किसी बस टार्मिनल से 2 बसे 10 मिनट के अन्तराल पर चलती हो, प्रत्येक बस ।
की चाल 20km/h रहती हो एक आदमी जो बस टुर्मिनल की तरफ भाग रहा हो बस
8मिनट के अन्तराल पर मिलने का दावा करता है, तो बस आदमी की चाल क्या होगं
Moving from a bus terminal to a distance of 10 minutes to 10 minutes, the
movement of each bus is 20km/h. A man who is running towards the Terminal
simply claims to meet at the interval of 8 minutes, then what will be the man's trick​

Answers

Answered by lkchandel
0

Answer:

The distance traveled by the leading bus in 10 minutes = 20*(10/60) = 10/3 Km

if the man is moving with X km/h speed in the bus direction

relative speed of man w.r.t to bus = 20 + X

now time taken by man to meet both buses

(10/3)/ (20+X) = (8/60)

after solving X= 5 km/h

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