18) PQ and RS are two equal chords of length 24 cm each which intersect each other at A. AR > AS. If AQ : AP = 1:3, then show that AP + AR = 36 cm.
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Answer:
12
2
−x
2
=AM
2
=8
2
−y
2
∴12
2
−8
2
=x
2
−y
2
=(x+y)(x−y)=x
2
−y
2
=(x+y)(x−y)=BP.PC
∴AP.PD=80 or 8×PD=80
∴PD=10 and AD=18
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