Math, asked by umabala1725, 1 year ago

18 questions fast plzzzzzzzZzzz

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Answered by brindhasarathy
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Answered by gaurav200370
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angle nCE=angle CEB=50°. (alternate angles)

then angle CEm+angle CEB=180°

angle CEm +50°=180°

then angle z =130°

angle CBE=180°- angle ABE

then angle CBE =70°

In triangle CBE ,

angle C+ angle B+ angle E =180°

x + 70 + 50 =180°

x = 180 - 120

x=60°

angle EBA + angle BAD =180°

110°+y=180°

y=70°

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