18. The floor of a bathroom with dimensions 3m x
2.4 m, is to be paved with tiles of dimensions
15 cm x 12 cm. Find,
(1) How many tiles are required?
(ii) What is the cost of paving at the rate of 200
per tile?
Answers
Answer:
The total number of tiles is 400.. The total cost of paving is ₹80,000.
Step-by-step explanation:
Length of the floor = 3m
= 300cm
Breadth of the floor = 2.4m
= 240cm
Area of the floor = L x B
= 300 x 240
= 72,000
The area of the floor is 72,000.. Now we need to find the area of one tile.
Length of tile = 15cm
Breadth of tile = 12cm
Area of a tile = L x B
= 15 X 12
= 180.
(i) Number of tiles required = Area of the floor ÷ Area of one tile
=
= 400 tiles.
∴We need 400 tiles.
(ii) Cost of paving = ₹200 x Number of Tiles
= ₹200 x 400
= ₹80,000
Answer:
(1) Required no of tiles = 4
(2) Total cost = $ 800
We have,
length of floor = 3 m
breadth of floor =2.4 m
.: Area of floor = Area of rectangle
Area of floor = length × breadth
= 3 × 2.4
= 7.2 Sq m
Dimensions of each tile,
L = 15 cm
B = 12 cm
Area of each tile = L× B
= 15 × 12
= 180 Sq cm
= 1.8 Sq m
(1) Required no of tiles,
= Area of floor/Area of each tile
= 7.2/1.8
= 4
hence, Required no of tiles = 4
(2) cost of paving each tile = $ 200
Thus,
cost of paving 4 tiles = 4 × 200
= $ 800
hence , Total cost = $ 800