Math, asked by guptamoolchandgupta5, 10 months ago

18. The floor of a bathroom with dimensions 3m x
2.4 m, is to be paved with tiles of dimensions
15 cm x 12 cm. Find,
(1) How many tiles are required?
(ii) What is the cost of paving at the rate of 200
per tile?​

Answers

Answered by Explorer123
3

Answer:

The total number of tiles is 400.. The total cost of paving is  ₹80,000.

Step-by-step explanation:

Length of the floor  = 3m

                                = 300cm

Breadth of the floor = 2.4m

                                 = 240cm

Area of the floor = L x B

                           = 300 x 240

                           = 72,000cm^{2}

The area of the floor is 72,000cm^{2}.. Now we need to find the area of one tile.

Length of tile = 15cm

Breadth of tile = 12cm

Area of a tile = L x B

                      = 15 X 12

                      = 180cm^{2}.

(i) Number of tiles required = Area of the floor ÷ Area of one tile

                                             = \frac{72000}{180}

                                             = 400 tiles.

∴We need 400 tiles.

(ii) Cost of paving = ₹200 x Number of Tiles

                              = ₹200 x 400

                              = ₹80,000

Answered by AkashDobriyal
0

Answer:

(1) Required no of tiles = 4

(2) Total cost = $ 800

We have,

length of floor = 3 m

breadth of floor =2.4 m

.: Area of floor = Area of rectangle

Area of floor = length × breadth

= 3 × 2.4

= 7.2 Sq m

Dimensions of each tile,

L = 15 cm

B = 12 cm

Area of each tile = L× B

= 15 × 12

= 180 Sq cm

= 1.8 Sq m

(1) Required no of tiles,

= Area of floor/Area of each tile

= 7.2/1.8

= 4

hence, Required no of tiles = 4

(2) cost of paving each tile = $ 200

Thus,

cost of paving 4 tiles = 4 × 200

= $ 800

hence , Total cost = $ 800

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