Question

18 years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is

Answer 1

let 18yr ago age of son is x than father's age is 3x
after 18 years( present)
father's age = 3x +18
son's age = x + 18
according to question father is twice as old as his son
than
3x+18=2(x+18)
3x+18=2x+36
3x-2x=36-18
x=18
present age of father = 3x+18
put the value of x. =3×18+18 =72
present age of son = x+18=18+18= 36
sum of present ages of father and son = 72+36=108

Answer 2

Answer:

Step-by-step explanation:

let 18yr ago age of son is x than father's age is 3x

after 18 years( present)

father's age = 3x +18

son's age = x + 18

according to question father is twice as old as his son

than

3x+18=2(x+18)

3x+18=2x+36

3x-2x=36-18

x=18

present age of father = 3x+18

put the value of x. =3×18+18 =72

present age of son = x+18=18+18= 36

sum of present ages of father and son = 72+36=108