Chemistry, asked by harshthegreat2540, 11 months ago

Calculate the enthalpy change when 2.38g of carbon monoxide vaporizes at its normal boiling point of enthalpy of vaporization of co is 6.04 kj/mol

Answers

Answered by BarrettArcher
18

Answer : The enthalpy change is 0.5134 KJ.

Solution : Given,

Mass of carbon monoxide = 2.38 g

Enthalpy of vaporization = 6.04 KJ/mole

Molar mass of carbon monoxide = 28 g/mole

The enthalpy change when 28 g carbon monoxide vaporizes at normal boiling point = 6.04 KJ/mole

and The enthalpy change for 2.38 g of carbon monoxide vaporizes at normal boiling point = \frac{6.04KJ/mole\times 2.38g}{28g}=0.5134KJ

Therefore, the enthalpy change is 0.514 KJ.

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